I am working with JChem for Excel (version 184.108.40.2066) and I have a used the chemical function "JCRotatableBondCount" to evaluate a series of compounds (such as the one attached).
was wondering how the rotatable bonds are calculated, since the number of rotatable bonds calculated for the attached compound is 1 according to JChem for Excel, but according to the criteria established by Veber in his original article (i.e. "Rotatable bonds were defined as any single bond, not in a ring, bound to a nonterminal heavy (i.e., non-hydrogen) atom. Excluded from the count were amide C-N bonds because of their high rotational energy barrier") it seems that the number of rotatable bonds would be 3 (two single C-O bonds and one single C-C bond).
Are not the single C-O bonds in this compound counted by JChem? Why? Which is the rotatable bond found by JChem?
Thanks in advance.