Hi!
Only two pKa values can be calculated with the command line that you sent. The last "number" is not a pKa value as you thought. The last two numbers 7 and 6 are separated with a " , " are the atomic "ID" of the ionizable acidic groups in the molecule.
Look at the attached figure. Atoms in the molecule are identified with a number as you can see. The "OH" group is the 7th atom and the "NH" group is the 6th atom in the molecule.
I have repeated the command line that is in question. The result is written into a txt file. The output is correct. There are the atom ID's under the "atoms" label.
cxcalc -o CNE_chemaxon.txt pKa -a 3 -b 0 CNE_chemaxon.sdf
id apKa1 apKa2 apKa3 atoms
1 8.66 14.95 7,6
I would propose to try this command as well. The pKa values of the two strongest adic and basic groups are plotted.
cxcalc -o CNE_chemaxon.txt pKa d:/ACTUAL/CNE_chemaxon.sdf
id apKa1 apKa2 bpKa1 bpKa2 atoms
1 8.66 14.95 2.44 -4.95 7,6,9,10
Alternativelly you would get the same result by manually settiing the count of the acidc and the basic groups what you want the pKa value for and to be echod into the output.
cxcalc -o CNE_chemaxon.txt pKa -a 2 -b 2 CNE_chemaxon.sdf
id apKa1 apKa2 bpKa1 bpKa2 atoms
1 8.66 14.95 2.44 -4.95 7,6,9,10
Can you see the "atoms" label on your output?
Jozsi